匹配括号内的内容并获取URL并使用RegExp PHP将其更改为img标记[重复]

I need to match something from content get the url from it and completely change the matched item. here is my content look like:

$content = "A quick brown fox {img:https://imageurl.com/fox.jpg} jumps over the lazy dog {img:https//:imageurl.com/dog.jpg}.";

I need it like this:

echo $content;


A quick brown fox <img src='https://imageurl.com/fox.jpg' style='width:100%' /> jumps over the lazy dog. <img src='https//:imageurl.com/dog.jpg' style='width:100%' />;

I can get the links using preg_match_all("/\{img:(.*?)\}/", $text, $matches); but don't know how to replace it.

Thanks in advance;

</div>

The solution is the data cutting between {}.

Try this:

$result = preg_replace("#\{img:(.*)\}#U",'<img src=\'$1\' style=\'width:100%\' />',$content);