如何将其解析为PHP对象？ [关闭]

I'm trying to parse site data using PHP + curl. And that's what I saw in the debug window in chrome: http://i.stack.imgur.com/xcJpL.png

Here is a server response below. How to parse it to PHP object?

Arr = new Array();

Arr[Arr.length] = new MeetingDetails();
Arr[Arr.length - 1].mode = 2;
Arr[Arr.length - 1].details = replaceLineBreakToHTML('');
Arr[Arr.length - 1].meetingTime =  CreateNewDateFromMiliInUTC(1432374300000);
var informationArr=new Array();
Arr[Arr.length - 1].cfInformationArr=informationArr;
Arr[Arr.length - 1].attendeeArray = new Array();
Arr[Arr.length - 1].attendeeArray[0] = new Array();
Arr[Arr.length - 1].attendeeArray[0][0] = htmlDecodeText('Sue',true);
Arr[Arr.length - 1].attendeeArray[0][1] = htmlDecodeTextWOlt('suew');

Arr[Arr.length] = new MeetingDetails();
Arr[Arr.length - 1].mode = 2;
Arr[Arr.length - 1].details = replaceLineBreakToHTML('');
Arr[Arr.length - 1].meetingTime =  CreateNewDateFromMiliInUTC(1431769500000);
var informationArr=new Array();
Arr[Arr.length - 1].cfInformationArr=informationArr;
Arr[Arr.length - 1].attendeeArray = new Array();
Arr[Arr.length - 1].attendeeArray[0] = new Array();
Arr[Arr.length - 1].attendeeArray[0][0] = htmlDecodeText('Tara ',true);
Arr[Arr.length - 1].attendeeArray[0][1] = htmlDecodeTextWOlt('suew');

Looks like a code, but how to make a PHP object from this?

Thanks for any ideas.

Solution:

<?php
$data = file_get_contents('scheduleonce.txt');
$data = explode("
", $data);
$arr = array();
$i = - 1;
foreach ($data as $string) {

    preg_match_all("#.title = htmlDecodeText\('(.*?)',true\);#i", $string, $matches);
    if (isset($matches[1][0])) {
        $i++;
        $arr[$i]['title'] = $matches[1][0];
    }

    preg_match_all("#.status = (.*?);#i", $string, $matches);
    if (isset($matches[1][0])) $arr[$i]['status'] = $matches[1][0];
}

print_r($arr);

You can do one thing, Use json encode and decode fujction.

First push array to json encode then push encode to decode.

$varObj = jason_decode( json_encode($arr)) ;