I need to echo html (which also contains a variable) and I keep getting Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting ',' or ';'
while ($line1 = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo '<h1 align = "center"><strong>Section:</strong></h1>.''.'<h1align="center"><strong>$line1 ['section_id']</strong></h1>';}
Basically, I need it to read Section: (and then whatever is retrived for Section ID, all on one line). What is the best way to go about outputting html is a situation lke this?
Your code is a trainwreck. Try this:
while ($line1 = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo '<h1 align = "center"><strong>Section:</strong></h1><h1 align="center"><strong>' . $line1['section_id'] . '</strong></h1>';
}
while ($line1 = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo '<h1 align = "center"><strong>Section:</strong></h1><h1align="center"> <strong>' . $line1 . ' ' . ['section_id'] .'</strong></h1>';}
there you go