获取'Y-m-d'的开始时间戳

Given a date string formatted Y-m-d (2014-4-11 for example), how can I get a UNIX timestamp of 12am the beginning of that day? Would it involve date_parse_from_format()?

Thanks

You can simply use strtotime()

$date = "2014-04-11";
$timestamp = strtotime($date);

which inturm gives you -

$d = date('Y-m-d H:i:s', $timestamp);  // 2014-04-11 00:00:00

Try online conversion to test - http://www.onlineconversion.com/unix_time.htm