显示数据库记录PHP [重复]

I am getting a problem with the program I created, a message like this appears

Undefined variable: html_response in C:\xampp\htdocs\

when I want to display a database record on my web page.

This is the script I created:

call-data.php

<?php
    $mysqli= mysqli_connect('localhost','sman10bdl','xx','x10x');
    $kls = $_POST['kelas'];
    $query = "SELECT * FROM data_siswa WHERE kls='$kls'";
     // Execute Query
    $result = mysqli_query($mysqli,$query);
    if (!$result) {
        printf("Error: %s
", mysqli_error($mysqli));
        exit();
    }
    $noUrut = 0;
    while($row = mysqli_fetch_array($result)){
        $noUrut++;
        $nis = $row["nis"];
        $nisn = $row["nisn"];
        $nama = $row["nama"];
        $kls = $row["kls"];
        $sex = $row["sex"];
        $alamat = $row["alamat"];
        $telp = $row["hanphone"];

        $html_response.= "<tr>
            <td align='center'>$noUrut</td>
            <td align='center'>$nis</td>
            <td align='center'>$nisn</td>
            <td align='left'>$nama</td>
            <td align='center'>$sex</td>
            <td align='center'>$alamat</td>
            <td align='center'>$telp</td>
        </tr>";
    }
    echo $html_response;
?>

I hope any body can give me solution. Thanks very much.

</div>

You have not declared the variable before adding to it.

Using .= only appends to the existing variable... it does not declare it and then append.

So your solution would be to declare $html_response before adding to it.

You are trying to append to variable $html_response, but you never define it. This way you are defining it only inside the while loop, so its not accessible outside of it.

The call $html_response .= 'something'; is basically shorthand for this:

$html_response = $html_response . 'something';

This should work:

$html_response = ''; // initialize with empty string

while ($row = mysqli_fetch_array($result)){
    // ...
    $html_response .= "...";
    // ...
}

echo $html_response;

I see your "answer" here with more explanation - you should update your question, not post an "answer" that does not answer anything :]

The latter problem is the same as you had before, you are still trying to append to not existing variable. Just use this instead (note the dot is not there):

$html_response = "<table>"; // define variable initialized with string