匹配实际字符串“％0”与正则表达式[关闭]

I'm trying to match the sub-string CONTENT=%0 using regular expressions. I have been trying for quite some time and nothing seems to work! Any ideas?

This one worked for me: /CONTENT=%0/

You don't need to use regex for this simple kind of task, but... you can if you want to... use regex pattern

CONTENT=%0

PHP code:

$pattern = '/CONTENT=%0/';
$s = preg_replace($pattern, $replacement, $s);

See this demo.