PHP - 从数据库中只删除一个表

I've searched a long time and didn't found correct answer for this question that i want to delete only one table from database. so i have this:

<?php

$database_name = "XXXXXX";

if (!$link = mysql_connect('XXXXXX', 'XXXXXX', 'XXXXXX')) {
  die("Could not connect: " . mysql_error());
}

$sql = "SHOW TABLES FROM $database_name";
if($result = mysql_query($sql)){

  while($row = mysql_fetch_row($result)){
    $found_tables[]=$row[0];
  }
}
else{
  die("Error, could not list tables. MySQL Error: " . mysql_error());
}

 foreach($found_tables as $table_name){
  $sql = "DROP TABLE $database_name.$table_name";
  if($result = mysql_query($sql)){
    echo "Success - table $table_name deleted.";
  }
  else{
    echo "Error deleting $table_name. MySQL Error: " . mysql_error() . "";
  }
}
?> 

it will list all tables from database and delete all of theme but i want to delete them one by one. something like this:

delete.php?item=ONE_OF_TABLE

drop table by querystring with table name or ...

First take a look on mysql function deprecated

Then your SQL-Syntax has to be edited by a WHERE table_name LIKE 'ONE_OF_TABLE'

or replace ONE_OF_TABLE by $_GET['item']

The code posted does exactly what you want - it drops tables one by one in a cycle. If you mean - "Show tables to end user, THAN drop them one by one" - you should print the result of SHOW TABLES query and expect some other user interaction.