（if和）语句的快捷方式

If there any way to write short cut code instead of this one

I want to say if page id is 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9 or 10 then show something and else show something else

<?PHP
if ($page[id]==1 || $page[id]==2 || $page[id]==3 || $page[id]==4 || $page[id]==5 || $page[id]==6 || $page[id]==7 || $page[id]==8 || $page[id]==9 || $page[id]==10){

echo "something";

}else{

echo "something else";
} 

?>

thanks that would helps me a lot for longer example since the ids are numbers 1,2,3...etc

You could do

<?PHP
if ($page['id'] >=1 && $page['id'] <=10){

  echo "something";

}else{

  echo "something else";
} 

you can use in_array.

if (in_array($page['id'], array(1,2,3,4,5,6,7,8,9,10)))
{
    echo "something";
}
else
{
   echo "something else";
}

In such cases you can usally use in_array() to compare a variable against a list of values. In your case you can combine it with range() (if it's a short consecutive numeric list) like so:

if (in_array($page[id], range(1,8))) {

Note that $page[id] should probably be $page["id"].

if($page['id'] > 0 and $page['id'] < 11) {
    echo 'something';
}

you can use ternary operator as below

echo ($page[id] >=1 && $page[id] <=10)?"something":"something else";

you can also use in_array to do similar condition

you can just use an if condition like if($page[id]>=1 && $page[id]<=10)..