通过php中的“变量”添加到目前为止的小时数不是静态的

I have stored the date and time in database like this 2015-06-31 14:00 And i want to add some hours to the date field through variable how can i add

<?php
//set an date and time to work with
$start = '2015-06-31 14:00';
$hours='05:00';

//display the converted time
echo date('Y-m-d H:i',strtotime("+{$hours} hours",strtotime($start)));
?>

Try this

<?php
$start = '2015-10-31 14:00';
$hours = '05:00';

$date = new DateTime($start);
$date->modify(sprintf("+%d hours", $hours));
echo $date->format("Y-m-d H:i");
?>

Output:

2015-10-31 19:00

Check this

//set an date and time to work with
$start = '2015-06-30 14:00';
$hours= 5;

//display the converted time
echo date('Y-m-d H:i',strtotime("+{$hours} hours",strtotime($start)));

The output is 2015-06-30 19:00