$a = "this is school of sachin";
$pattern = "sch";
I want to get the position of the pattern matched from the end. For example in this case, sch matches school -- so the position of the pattern should be 3, i.e. from the end:
as mentioned below the index for the word school are arranged in this manner,so if the match of sch is successful than the position from the end of the word which is getting matched(school) and to the start of the pattern(from the end) should be returned.
s c h o o l
5 4 3 2 1 0
^---^
matched pattern.
I have tried strpos() but could not make it to serve my purpose.
echo strpos($a, $pattern); // this is wrong
The output of strpos() should be 3 according to my question.
<?php
$a = "this is school of sachin";
$pattern = "sch";
$words = explode(" ", $a);
$pattern = strrev($pattern);
foreach($words as $word){
$pos = strpos(strrev($word), $pattern);
if($pos !== false){
print($pos);
break;
}
}
?>
OR
<?php
$a = "this is sachinùs school of sachin";
$pattern = "sach";
if(preg_match("/[^ [:punct:]]*".$pattern."([^ [:punct:]]*)/u", $a, $match)){
print(mb_strlen($match[1], "UTF-8"));
if($pattern == $match[0]){
print(" (full word)");
}
}
?>
Without the whole approach suggested by Sharanya
$haystack = 'this is a verygood school of sachin';
$pattern = 'sch';
$match = strstr($haystack, $pattern);
for ($i = 0;$i < strlen($match);$i++) {
if ($match[$i] == ' ') {
$match = substr($match, 0, $i);
break;
}
}
$result = strlen($match) - strlen($pattern);
echo $result;
Note that it will find the FIRST occurence starting from left, so for example 'schschool' would output 6.
NOTE - This also, tells you if the found word is full word or not
Take a look - http://3v4l.org/i94Lr
$pattern = "sch";
$b = explode(' ','this is school of sachin');
$b = array_reverse($b);
for($i=0;$i < count($b);$i++){
if(strpos($b[$i],$pattern) !== false){
echo $i+1;
$full = ', not a full word';
if($b[$i] == $pattern){
$full = ', full word';
}
echo $full;
break;
}
}
Use a regular expression with word boundaries (\b) to find the word that matches the supplied pattern and then capture everything after the pattern using a capturing group. Then, simply return the length of that string:
$a = "this is school of sachin";
if (preg_match('/\b(sch(\w+))\b/', $a, $matches)) {
echo strlen($matches[2]); // => 3
}
If you also want to account for non-English characters, then you can use the u modifier:
$a = "this is sachinùs school of sachin";
if (preg_match('/\b(sch(\w+))\b/u', $a, $matches)) {
echo strlen($matches[2]); // => 3
}