I have an job application form that sends an email with the information, and should also insert the values from the form (the values of which are imported into the handler.php seen below at the top) into a table in a database on the server.
However, it's not inserting the values, and I can't figure out why.
I actually took this script from my client's old version of the website on a different domain and server, and it's still working perfectly on that one, so I can't figure out why it's not working here. The only thing I've changed is the database details. At one point I thought the issue might be because mysql_connect etc. is deprecated in favour of mysqli-equivalents, but the client's server is still running PHP 5.3, so that shouldn't be the issue.
Via PHPMyAdmin, I have a database, and a table called 'team'. I create all the columns according to the original setup on the old website, so that each item you see in the INSEERT query down below will have somewhere to go.
Am I missing something in my SQL connection code? The username, password, domain and database are all correct...
$date = date("d/M/Y");
$name = Trim(stripslashes($_POST['name']));
$dob = Trim(stripslashes($_POST['dob']));
$contact = Trim(stripslashes($_POST['contact']));
$email = Trim(stripslashes($_POST['email']));
$preferredCity = Trim(stripslashes($_POST['preferredCity']));
$nightsMo = Trim(stripslashes($_POST['nightsMo']));
$nightsTu = Trim(stripslashes($_POST['nightsTu']));
$nightsWe = Trim(stripslashes($_POST['nightsWe']));
$nightsTh = Trim(stripslashes($_POST['nightsTh']));
$nightsFr = Trim(stripslashes($_POST['nightsFr']));
$nightsSa = Trim(stripslashes($_POST['nightsSa']));
$nightsSu = Trim(stripslashes($_POST['nightsSu']));
$ownCar = Trim(stripslashes($_POST['ownCar']));
$previousWork = Trim(stripslashes($_POST['previousWork']));
if (Trim($nightsMo)=="") $nightsMo="NULL";
if (Trim($nightsTu)=="") $nightsTu="NULL";
if (Trim($nightsWe)=="") $nightsWe="NULL";
if (Trim($nightsTh)=="") $nightsTh="NULL";
if (Trim($nightsFr)=="") $nightsFr="NULL";
if (Trim($nightsSa)=="") $nightsSa="NULL";
if (Trim($nightsSu)=="") $nightsSu="NULL";
if (Trim($ownCar)=="") $ownCar="NULL";
$username="XXX";
$password="XXX";
$database="XXX";
mysql_connect("example.co.uk",$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
mysql_query("INSERT INTO team (t_date, t_name, t_dob, t_contact, t_email, t_preferredCity, t_nightsMo, t_nightsTu, t_nightsWe, t_nightsTh, t_nightsFr, t_nightsSa, t_nightsSu, t_ownCar, t_previousWork, t_picture) VALUES ('$date', '$name','$dob','$contact','$email','$preferredCity',$nightsMo,$nightsTu,$nightsWe,$nightsTh,$nightsFr,$nightsSa,$nightsSu,$ownCar,'$previousWork', '$filePath')");
mysql_close();
Unclear what could be the cause, but refactored your code to streamline & simplify things so it’s easier to debug.
The first thing I did was take all of your $_POST checks into a structure that uses one main array ($post_array) and then rolls through that array to process the values & assign them to similarly named variables.
Additionally, I added a $result string check for the mysql_query which then does a check to see if that is even returned. And if it fails, show us what the error is via mysql_error(). That should be the key to help you debug what is happening.
$date = date("d/M/Y");
// Set the post values array.
$post_array('name','dob','contact','email','preferredCity','nightsMo','nightsTu','nightsWe','nightsTh','nightsFr','nightsSa','nightsSu');
// Role through the post values array.
foreach($post_array as $post_key => $post_value) {
$$post_key = isset($_POST[$post_key]) ? Trim(stripslashes($_POST[$post_key])) : null;
}
$username="XXX";
$password="XXX";
$database="XXX";
mysql_connect("example.co.uk",$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query = "INSERT INTO team (t_date, t_name, t_dob, t_contact, t_email, t_preferredCity, t_nightsMo, t_nightsTu, t_nightsWe, t_nightsTh, t_nightsFr, t_nightsSa, t_nightsSu, t_ownCar, t_previousWork, t_picture) VALUES ('$date', '$name','$dob','$contact','$email','$preferredCity','$nightsMo','$nightsTu','$nightsWe','$nightsTh','$nightsFr','$nightsSa','$nightsSu','$ownCar','$previousWork', '$filePath')";
// Run the query & return the result.
$result = mysql_query($query);
// Check the mysql query result. If there is none, there is an error. So tell us what the error is.
if (!$result) {
die('Invalid query: ' . mysql_error());
}
mysql_close();
Also, unrelated but worth pointing out is mysql_* extensions are depreciated in PHP 5.3 & PHP 5.4. You should switch to mysqli_* extensions since mysql_* extensions with be eliminated in PHP 5.5.