错误：mysql_fetch_array需要资源，布尔给定[重复]

I have this PHP code:

$con = mysqli_connect("localhost","root","","dbjobsheetsf");
$sql1 = "SELECT colDate FROM tbljs ";
$queryR = mysql_query($sql1);

$p = 0;

echo "<select name=\"jsGetDate\">";

while($r = mysql_fetch_array($queryR)) {
    echo "<option value=".$r["colDate"].">".$r["colDate"]."</option>"; 
}
echo "</select>";

mysqli_close($con);

I'm getting the error:

mysql_fetch_array() expects parameter 1 to be resource, boolean given

Is there anyway to solve this problem?

Problem Solved Thank you sir John Robertson you were a big help!

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Be consistent on using mysqli_* functions otherwise it will mess up your program. So use mysqli_* functions since mysql_* functions are deprecated and will no longer be used in the future.

NOTICE: mysqli_query requires two parameters the $link and the query. Make sure that you are doing the query to the exact table and table column

$con = mysqli_connect("localhost","root","","dbjobsheetsf");
$sql1 = "SELECT colDate FROM tbljs ";
$queryR = mysqli_query($con, $sql1);   

$p = 0;

echo "<select name=\"jsGetDate\">";

while($r = mysqli_fetch_array($queryR)) {   
    echo "<option value=".$r["colDate"].">".$r["colDate"]."</option>"; 
}
echo "</select>";

mysqli_close($con);

boolean always happen when you have input wrong table . are you sure that your table name is tbljs ? i also have experienced this. you should try look out on your $con and your table name. if they are correct, i think there are no error in mysql_fetch_array

Dont mix mysql and mysqli

change the following lines to mysqli

$con = mysqli_connect("localhost","root","","dbjobsheetsf");
$sql1 = "SELECT colDate FROM tbljs ";
$queryR = mysqli_query($con, $sql1);

$p = 0;

echo "<select name=\"jsGetDate\">";

while($r = mysqli_fetch_array($queryR)) {
    echo "<option value=".$r["colDate"].">".$r["colDate"]."</option>"; 
}
echo "</select>";

mysqli_close($con);