使用foreach php将数据插入到sql表中

I have a form, that sends multiple seats to a php file. I created a foreach loop to insert each seat into sql. For some reason i am able to get all the information i need to send it but it wont insert.

I dont know if it has something to do with foreign keys? But what i want to do is show what email selected what seat. I also want to disable each seat when it is sent to sql.

sql side

This is my output.

    You are currently in database admin.


admin@airways.com
1A
1B
1C
Data added successfully.
Back to seating.

This is my flightselect.php

            <?php
    error_reporting(E_ALL);
    ini_set('display_errors',1);
    include_once 'includes/db_connect.php';
    include_once 'includes/functions.php';
    sec_session_start();

if (login_check($mysqli) == true) {
    $logged = 'in';
} else {
    $logged = 'out';
}
                $username = $_SESSION['username'];
                echo  '<p>You are currently '.$logged. ' database '.$username. '.</p><br>';

                $getemail = mysqli_query($mysqli, "SELECT email FROM members WHERE username = '$username' ");
                $email = '';
                while($gear = mysqli_fetch_array( $getemail )) {
                    echo $gear['email'];
                    $email = $gear['email'];
                } 

                echo $gear."<br>";

    if(isset($_POST['seatme'])){
        if(!empty($_POST['flight'])){
            foreach($_POST['flight'] as $key=>$selected){
                echo $selected."<br>";
                $result = mysqli_query($mysqli, "INSERT INTO seating (seat_id, email, flight_id) 
                                                    VALUES ('$selected', '$gear', '1' )");
            }
        }
    }
        echo "<font color='green'>Data added successfully.";
        echo "<br/><a href='user.php'>Back to seating.</a>";
?> 

You need a brackets after the VALUES keyword...

       if (!mysqli_query($mysqli, "INSERT INTO seating (seat_id, email, flight_id) 
                                   VALUES ('$selected', '$gear', '1' )"))  {
                 printf("Error: %s
", $mysqli->error);
       }

You should also learn about prepared statements as they make your SQL more secure.