我在php中编写了一个sql查询，任何人都建议这段代码可以工作吗？

$data= mysqli_query($con,"SELECT *, ACOS( SIN( RADIANS( lat ) ) * SIN( RADIANS( '$slat' ) ) + COS( RADIANS( lat ) ) * COS( RADIANS( '$slat' )) * COS(RADIANS( lon ) - RADIANS( '$slon' )) ) * 6380 AS distance FROM doner WHERE ACOS( SIN( RADIANS( lat ) ) * SIN( RADIANS( '$slat' ) ) + COS( RADIANS( lat) ) * COS( RADIANS( '$slat' )) * COS( RADIANS( lon ) - RADIANS( '$slon' )) ) * 6380 < '$dist' AND blood='$blood' ORDER BY distance");

Tell me if I am wrong but, it seems to be your first topic on this site. My advice is to put this code in "code sample" like this if you want to increase your chance someone answer your question :

$request = "
        SELECT *, ACOS( SIN( RADIANS( lat ) ) * SIN( RADIANS( '$slat' ) ) + COS( RADIANS( lat ) ) * COS( RADIANS( '$slat' )) * COS(RADIANS( lon ) - RADIANS( '$slon' )) ) * 6380 AS distance 
        FROM doner 
        WHERE ACOS( SIN( RADIANS( lat ) ) * SIN( RADIANS( '$slat' ) ) + COS( RADIANS( lat) ) * COS( RADIANS( '$slat' )) * COS( RADIANS( lon ) - RADIANS( '$slon' )) ) * 6380 < '$dist' 
        AND blood='$blood' 
        ORDER BY distance
";

$data= mysqli_query($con, $request);

For my own opinion, it's difficult to have an idea of what this code does (SQL meaningly) because we haven't your data bases, tables, and no clue of which calculus do.