OK so I set up a new server (droplet on DigitalOcean).
Say the url is 55.55.555.555 and my file file5.php was added to folder /home/user5 using WinSCP
What would the URL in my AJAX request look like, letter for letter?
Right now, for testing on my local EasyPHP server, it looks like this:
request.open( "POST" , "file5.php" , true );