如果页面名称与子文件夹的名称相同，则显示页面

So, I have 4 folders in my public folder: js, css, images, fonts (yes, i should put all in one folder). I also have a route which is pointing to an /images page. The problem is, when I open the images page, it throws a 404 error. Are there any solutions for this, or I have to rename the folder or the page. (The page names will be dynamic, so if the user creates a page named "anotherPage" it will be /anotherpage.)

routes.php

Route::get('/{pagename?}', 'PageController@index');

.htaccess

<IfModule mod_rewrite.c>
<IfModule mod_negotiation.c>
    Options -MultiViews
</IfModule>

RewriteEngine On

# Redirect Trailing Slashes If Not A Folder...
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^(.*)/$ /$1 [L,R=301]

# Handle Front Controller...
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^ index.php [L]

If i understand your question correctly.

You can have same name as your folders BUT, if a file with name upload exist within the folder upload (upload/upload.ext). It will always direct to folder not the file and try to get upload/index.ext.

This is a default yet confusing behavior which can lead to ambiguous results. Never use same folder names and files.

The route for the images page must be defined before the {pagename} route.