批处理文件错误句柄

I have batch file that execute my php script, but I dont know how to handle the empty argument, can you help me?

this is my batch script

echo off
set phppath=%1
set resultfolder=%2
set jsonfile=%3
shift
shift
shift

set PHP_HOME=%phppath%
set PATH=%PATH%;%PHP_HOME%
echo Set PHP_HOME in "%phppath%"
echo Locate result in folder "%resultfolder%"
echo JSON file is "%jsonfile%"


pause;
php -f cxense_json_to_xml.php %resultfolder% %jsonfile%

@echo off
set phppath=%1
set resultfolder=%2
set jsonfile=%3
set PHP_HOME=%phppath%
set PATH=%PATH%;%PHP_HOME%
echo Set PHP_HOME in "%phppath%"
echo Locate result in folder "%resultfolder%"
echo JSON file is "%jsonfile%"
php -f cxense_json_to_xml.php %resultfolder% %jsonfile%
Pause

And the batch would have to be started like this:

Batch.bat "path to PHP" "path to result folder" "name of jsonfile"

there is no semicolon after pause.