PHP,MySQL:显示用户'休假'

I have this code below on how to show who is currently "on leave" today.

$today = date("j F, Y");//date format is->1 December, 2015
$result = $db->query("SELECT name, date_apply, leave_from, leave_end, num_days, reason FROM applied_user  WHERE status = 'Approved' AND leave_from = '$today'");

My question is, is it possible to show all approve leave before the current day?thanks..

Try this

$today = date('d F, Y'); //current date (11 December, 2015)
$result = $db->query(
    "SELECT name, date_apply, leave_from, leave_end, num_days, reason 
    FROM applied_user  
    WHERE status = 'Approved' 
    AND leave_from >= '$today'");

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