I have my table structure like as below:
tbl1
id prodid prodname height cost category
-----------------------------------------
1 1 Test 5 54 ABC
2 5 Test1 6 85 DEF
3 8 Test2 8 20 DEF
4 2 Test3 4 10 GHI
5 3 test4 8 58 ABC
6 4 Test5 84 878 ABC
tbl2
id(FK of pid) color intensity vibrance
-----------------------------------------
1 red 5 NA
5 pink 0.5 8 ..and so on
Now i want the output like as below,
ABC
----
Test ... & other parameters
test4 ... & other parameters
Test5 ... & other parameters
DEF
---
Test1 ... & other parameters
Test2 ... & other parameters
GHI
----
Test3 ... & other parameters
"SELECT tbl1.*,tbl2.* from tbl1 LEFT JOIN tbl2 on tbl1.prodid=tbl2.id;
i tried to show cat as below:
$category="";
foreach($all as $row){
if ($row['category'] != $category && !empty($row['category'])) {
echo $row['category']; $category=$row['category'];
}
echo $row['othercolumns'];
}
But it is not grouping... It is repeating every time.
You can use PDO, which has a nice feature for you with PDO::FETCH_GROUP
option in PDOStatement::fetchAll() function. Firstly in your query, make category
the first column, like this way :
SELECT tbl1.category, tbl1.* from tbl1 LEFT JOIN tbl2 on tbl1.pid=tbl2.id;
Then run the query in PDO
and fetchAll
with PDO::FETCH_GROUP
$sth = $dbh->prepare($query);
$sth->execute();
$result = $sth->fetchAll(PDO::FETCH_ASSOC|PDO::FETCH_GROUP);
print_r($result);
//Result will be something like this:
Array (
[ABC] => Array
[0] => Array
(
[id] => 1,
[prodid] => 1,
[prodname] => "test",
[height] => 5,
[cost] => 54,
[category] => "ABC",
),
[1] => Array
(
...
),
....
),
[DEF] => Array
(
...
),
....
)
You can select all and the time your are fetching the result in PHP simply search for the category.
SQL query:
SELECT tbl1.*, tbl2.*, tbl2.id AS id2
FROM tbl1 AS tbl1
LEFT JOIN tbl2 AS tbl2 ON(prodid = id2)
PHP Part:
while ($row = mysqli_fetch_array($rows)){
// handle $row[category] using switch or ifs
then put each in array to display the html part
}