I have the path to an image file /files/uploads/1 but as you can see, I don't have an extension so I can't display the image. How can I get the extension of the file so I can display it? Thanks!
EDIT: Here is come code I have tried. BMP, PNG, JPG, JPEG and GIF are the only possible extensions, but $path ends up never getting assigned a value.
$exts = array('bmp','png','jpg','jpeg','gif');
foreach ($exts as $ext) {
if (file_exists("/files/uploads/" . $id . "." . $ext)) {
$path = "/files/uploads/" . $id . "." . $ext;
}
}
Personally, I had a problem where I had an unnecessary slash (/) before my path in the file_exists check, but the solution to the question is still the same.
$exts = array('bmp','png','jpg','jpeg','gif','swf','psd','tiff','jpc','jp2','jpx','jb2','swc','iff','wbmp','xbm','ico');
foreach ($exts as $ext) {
if (file_exists("files/uploads/" . $id . "." . $ext)) {
$path = "/files/uploads/" . $id . "." . $ext;
}
}
You don't need a file extension to show an image.
<img src="/files/uploads/1">
Will show the image. It's the same way the placehold.it images work
<img src="http://placehold.it/350x150">
First of all , I think when you get the file name for the image that means no need to add extension , so you have the file name and image folder
it should simply look like this :
$fullpath = ('uploadword/'.$filename);
// then call it
<img src='".$fullpath."'>
The normal scenario to upload all the images in specific folder then get the filename and save it in data base
move_uploaded_file($file_tmp,"upload/".$filename);
Some professional make it more sophisticated to make filename unique ,because they expected some duplicated values and many reasons , here is one simple technique :
$anynameorfunction = "";// random number etc...
$newname = $anynameorfunction.$filename;
move_uploaded_file($file_tmp,"upload/".$newname);
So, when they call it again it should be simple like this
$fullpath = ('uploadword/'.$newname);
// then call it
<img src='".$newname."'>
This is in very simple way and i wish you get what i mean