否JsonResponse即使单个数据为空也获得

  {"futsal_id":"59",
    "description":[{
    "futsal_id":"59",
    "futsal_desc":"This is great futsal"}],

    "features":[{"futsal_id":"59","futsal_feat":"free 4 bottles of water"}],
    "dimension":null,
    "no_of_futsal":null,
    "opening_hrs":null,
    "price_weekdays_price1":[{
            "futsal_id":"59",
            "price_id":"1",
            "start_time":"6am",
            "end_time":"10am",
            "price":"1000"}],
    "price_weekdays_price2":[{
            "futsal_id":"59",
            "price_id":"2",
            "start_time":"10am",
            "end_time":"3pm",
            "price":"1200"}],
    "price_weekdays_price3":[{
            "futsal_id":"59",
            "price_id":"3",
            "start_time":"3pm",
            "end_time":"9pm",
            "price":"1300"}],
    "price_weekend_price1":null,
            "price_weekend_price2":null,
            "price_weekend_price3":null,
    "images":[],
    "image_count":0,
    "news":null}

This is My JsonResponse from PHP. I cannot get any of this response in android studio with these response because of present null data in these response. If no null data are present, response.getString() has all these data but response.getString has no response because of null data. What might be the problem?

    class ShowResult extends AsyncTask<Void, Void, String[]> {

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        pd.show();
    }

    @Override
    protected void onPostExecute(String[] aVoid) {
        super.onPostExecute(aVoid);
        pd.cancel();
        txt.setText(result[0]);
      }

    @Override
    protected String[] doInBackground(Void... params) {
        try {
            Log.d("sssssssssssssss", "sadf");

            URL url = new URL("http://futsalgroove.s4generation.com/app/android_c/show_details/");
            HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
            urlConnection.setDoOutput(true);
            urlConnection.setRequestMethod("POST");

            String urlParameters = "id=" + bundle.getString("id");
            //sending the parameter using DataOutputStream
            DataOutputStream wr = new DataOutputStream(urlConnection.getOutputStream());
            wr.writeBytes(urlParameters);
            wr.flush();
            wr.close();

            //Reading the data or response from the PHP file
            BufferedReader in = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));

            Log.d("sssssssssssssss", "iii" + in);
            String inputLine;
            StringBuffer response = new StringBuffer();

            while ((inputLine = in.readLine()) != null) {
                response.append(inputLine);
                Log.d("Detail Outputss", inputLine);
            }
            in.close();
            //Using the JasonObject from php
            Log.d("Detail Outputsss", "" + response.toString());

            JSONObject json = new JSONObject(response.toString());

            JSONArray description = json.getJSONArray("description");
            JSONObject descObj = description.getJSONObject(0);

            result[0] =  descObj.getString("futsal_desc");
            Log.d("DetailOut","" + result[0]);
     }

       } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } catch (JSONException e) {

        }
        return result;
    }
}

Replace your code

JSONObject json = new JSONObject(response.toString());
JSONArray description = json.getJSONArray("description");
JSONObject descObj = description.getJSONObject(0);
result[0] =  descObj.getString("futsal_desc");
Log.d("DetailOut","" + result[0]);

with

JObject json = JObject.Parse(response.toString());
JArray description = (JArray)json["description"];
JObject descObj = (JObject)description[0];
result[0] = descObj["futsal_desc"].ToString();
Log.d("DetailOut","" + result[0]);

may be this will work. for JObject use Newtonsoft.Json.Linq on top

using Newtonsoft.Json.Linq;