论坛响应错误:PRIMARY键的重复条目

I have been writing some code for a forum and am new to PHP, but I have run into some trouble. When I test the program by entering an answer, I get a web page that says "ERROR".

After changing echo "ERROR" to echo mysql_error(), the webpage changed to this:

Notice: Undefined index: id in C:\xampp5\htdocs\add_answer.php on line 14

Notice: Undefined index: a_name in C:\xampp5\htdocs\add_answer.php on line 30

Notice: Undefined index: a_email in C:\xampp5\htdocs\add_answer.php on line 31

Notice: Undefined index: a_answer in C:\xampp5\htdocs\add_answer.php on line 32 Duplicate entry '1' for key 'PRIMARY'

<?php

$host="localhost"; // Host name 
$username=""; // Mysql username 
$password=""; // Mysql password 
$db_name="test"; // Database name 
$tbl_name="forum_answer"; // Table name 

// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");

// Get value of id that sent from hidden field 
$id = $_POST['id'];

// Find highest answer number. 
$sql="SELECT MAX(a_id) AS Maxa_id FROM $tbl_name WHERE question_id='$id'";
$result=mysql_query($sql);
$rows=mysql_fetch_array($result);

// add + 1 to highest answer number and keep it in variable name "$Max_id". if there no answer yet set it = 1 
if ($rows) {
    $Max_id = $rows['Maxa_id']+1;
}
else {
    $Max_id = 1;
}

// get values that sent from form 
$a_name = $_POST['a_name'];
$a_email = $_POST['a_email'];
$a_answer = $_POST['a_answer']; 

$datetime=date("d/m/y H:i:s"); // create date and time

// Insert answer 
$sql2="INSERT INTO $tbl_name(question_id, a_id, a_name, a_email, a_answer, a_datetime)VALUES('$id', '$Max_id', '$a_name', '$a_email', '$a_answer', '$datetime')";
$result2=mysql_query($sql2);

if($result2){
    echo "Successful<BR>";
    echo "<a href='view_topic.php?id=".$id."'>View your answer</a>";

    // If added new answer, add value +1 in reply column 
    $tbl_name2="forum_question";
    $sql3="UPDATE $tbl_name2 SET reply='$Max_id' WHERE id='$id'";
    $result3=mysql_query($sql3);
}
else {
    echo "ERROR";
}

// Close connection
mysql_close

();
?>

For the moment I am not concerned with security, as I intend to fix security issues later down the track.

You have a race condition in your code. When multiple users hit the database at the same time, they will eventually read the same $Max_id and subsequently try to insert the same $Max_id + 1. Eg.:

  1. User 1 selects id 42
  2. User 2 selects id 42
  3. User 1 inserts id 43
  4. User 2 inserts id 43

You need to declare the primary key column with the AUTO_INCREMENT attribute (or simply declare it as a SERIAL). This way, the database engine will automatically update the id with a guaranteed unique value when you insert new rows.