When i use this type of code
<?php echo get_sub_field('slide_image')['url']; ?>
then it's give me a
Parse error: syntax error, unexpected '[', expecting ',' or ';' in /home/sites/xyz.com/public_html/wp-content/themes/abc/partials/banner-images.php on line 9
this sort of error so what can i do in this situation. my total code is below
<?php if(have_rows('banner_slides')): // if have rows ?>
<div class="slideshow slideshow--banner" data-palm="palm-hidden">
<span id="prev" class="cycle-prev"><</span>
<?php while ( have_rows('banner_slides') ) : the_row(); // Loop through slides ?>
<div class="slideshow__slide" style="background-image: url(<?php echo get_sub_field('slide_image')['url']; ?>);">
It depends on what the return type of your sub-field is(you can set this while editing the sub-field). It will either by an array, an image url, or an image id.
If it's an array:
$img = get_sub_field('slide_image');
<div class="slideshow__slide" style="background-image: url(<?php echo $img['url']; ?>);">
If it's a url:
$img = get_sub_field('slide_image');
<div class="slideshow__slide" style="background-image: url(<?php echo $img; ?>);">
If it's an id:
$img = get_sub_field('slide_image');
<div class="slideshow__slide" style="background-image: url(<?php echo get_permalink($img); ?>);">
Object:
$img = get_field('slide_image');
<div class="slideshow__slide" style="background-image: url(<?php echo $img['url']; ?>);">
URL:
<?php if( get_field('slide_image') ): ?>
<div class="slideshow__slide" style="background-image: url(<?php the_field('slide_image'); ?>);">
<?php endif; ?>
ID:
<?php
$img = get_field('slide_image');
$size = 'full';
if( $img ) {
<div class="slideshow__slide" style="background-image: url(<?php echo wp_get_attachment_image( $img, $size ); ?>);">
}
?>