I want to parsing data from homepage on this url. As you can see this url is HTML file and I read below:
// Create a DOM object from a HTML file
$html = file_get_html('test.htm');
so I just type a code below
include "simple_html_dom.php";
$html = file_get_html('eecs.kookmin.ac.kr/site/computer/notice.htm');
echo $html->plaintext;
The error message is:
Error message Warning: file_get_contents(eecs.kookmin.ac.kr/site/computer/notice.htm): failed to open stream: No such file or directory in C:\Bitnami\wampstack-5.6.27-0\apache2\htdocs\simple_html_dom.php on line 76
what should I do?
You can get the HTML code using the Snoopy Class (https://sourceforge.net/projects/snoopy). Next code displays the HTML code inside of a <textarea> tag, then it displays the page itself, copy-paste next code in a PHP file and open it in your browser:
<!DOCTYPE html>
<html>
<head>
<META HTTP-EQUIV="Content-Type" CONTENT="text/html; charset=euc-kr">
<META HTTP-EQUIV="Content-language" CONTENT="ko">
</head>
<body>
<?php
require("Snoopy.class.php"); // ◄■■ GET SNOOPY FROM https://sourceforge.net/projects/snoopy
$snoopy = new Snoopy;
$snoopy->fetch("http://eecs.kookmin.ac.kr/site/computer/notice.htm");
$html = mb_convert_encoding( $snoopy->results, "UTF-8", "EUC-KR" ); // ◄■■ GET HTML CODE.
echo "<textarea rows='25' cols='80'>$html</textarea>"; // ◄■■ DISPLAY THE HTML.
echo $html; // ◄■■ DISPLAY THE WEBPAGE.
?>
</body>
</html>
The Snoopy Class is only one file, make sure the file is in the same directory your PHP file is.