PHP - MYSQL:无法识别表中的数据

this is my code for a login system. I have a table called Users2 with the following columns: userID, prenume, nume, nicknamee, parola (which is password) and tara. What I'm trying to do is this: a user types in his username & password. clicks submit and after clicking submit he gets the message if he's connected

<form method="post">
Username: 
<input type="text" name="nicknameee" placeholder="Username">
<br> 
Password: 
<input type="password" name="passwordd" placeholder="Password">
<br> 
<input type="submit" name="Submit2" value="submit"> 
<br>
<?php 
if (isset($_POST['Submit2'])) { 

    $result1 = $conn->query("SELECT nicknamee, parola FROM Users2 WHERE nicknamee='$_POST[nicknameee]' AND parola='$_POST[passwordd]' ");

    if (mysql_num_rows($result1)>0){
        echo "We are connected";
    }
    else{
        echo "INCORRECT";
    }

 } 
?>
</form>

The thing is I get this:

(the username and password form + submit button) and then: Warning: mysql_num_rows() expects parameter 1 to be resource, object given in /home/u381189183/public_html/login.php on line 30 INCORRECT

Because the result returned by the query is an object and not a resource you have to use $result1->num_rows in this case:

if (isset($_POST['Submit2'])) { 

    $result1 = $conn->query("SELECT nicknamee, parola FROM Users2 WHERE nicknamee='$_POST[nicknameee]' AND parola='$_POST[passwordd]' ");

    if ($result1->num_rows > 0){
        echo "We are connected";
    }
    else{
        echo "INCORRECT";
    }

 } 

Also you should switch to at least mysqli. Maybe PDO. And use prepared statements.