Laravel AJAX，JS，Php 404error

I have two connected <select> . The first one is static,the second one is depends of the first select value. I have a problem:http://localhost/ajax-model?make_id=8 404 (Not Found) The page where is the two select.

{{Form::open(array('url'=>'','files'=>true))}}
    <div class="form-group">
        <label for="make">Make</label>
        <select class="form-control input-sm" name="make" id="make">
        @foreach($make as $makes){
            <option value="{{$makes->id}}">{{$makes->title}}</option>
        }
        @endforeach
        </select>
    </div>
    <div class="form-group">
        <label for="model">Make</label>
        <select class="form-control input-sm" name="model">
            <option value=""></option>
        </select>
    </div>
{{Form::close()}}
<script>

$('#make').on('change', function(e){
    console.log(e);
    var make_id=e.target.value;
    //ajax

    $.get('/ajax-model',{make_id:make_id},function(data){
        //succes data
        console.log(data);
        alert(data);
    });
});

</script>

In a route:

Route::get('/ajax-model',function(){
    $make_id=Input::get('make_id');
    $model=CarModel::where('make_id','=',$make_id)-get();
    return Respone::json($model);
});

In a CarModel class:

class CarModel extends Model
{
    protected $fillabe=['make_id','title'];
}

I read a lot about that one,and everybody say,the CSRF_token,I added to the layout:

<meta id="token" name="token" content="{{csrf_token()}}">

So,any idea?

first error is your passing url, you should change it like-

$.get('{{url('/')}}/ajax-model',{make_id:make_id},function(data){
    //succes data
    console.log(data);
    alert(data);
});