格式化给定日期与DateTime，得到给定日期和今天日期作为结果

function getMonthExceptions(){

    $countTimeline = $_POST['hiddenCountTimeline'];

    If($_POST['timeline_0Start']!=""){

        $exceptionList = array();

        for($d=0; $d<=2; $d++){

            If($countTimeline<=$d){

                $startTimeline = $_POST['timeline_' . $d . 'Start'];
                $endTimeline = $_POST['timeline_' . $d . 'End'];

                $begin = new DateTime($startTimeline);
                $endUnmodified = new DateTime($endTimeline);

                $end = $endUnmodified->modify( '+1 day' );

                $daterange = new DatePeriod($begin, new DateInterval('P1D'), $end);

                foreach($daterange as $date){
                    array_push($exceptionList, $date->format("Y-m-d"));
                }

            }

        }

        return($exceptionList);
    }
}

I use this function to get some dates from input fields and save them into an array.

My problem:

If I format $startTimeline with new DateTime() and print $begin, I get this result, which is the given date (2017-02-01) and todays date two times (2017-02-16):

DateTime Object ( [date] => 2017-02-01 00:00:00.000000 [timezone_type] => 3 [timezone] => Europe/Berlin ) DateTime Object ( [date] => 2017-02-16 12:45:32.000000 [timezone_type] => 3 [timezone] => Europe/Berlin ) DateTime Object ( [date] => 2017-02-16 12:45:32.000000 [timezone_type] => 3 [timezone] => Europe/Berlin ) 

But it should be like that:

DateTime Object ( [date] => 2017-02-01 00:00:00.000000 [timezone_type] => 3 [timezone] => Europe/Berlin )

Any ideas?

Edit: Solved it by deleting If($countTimeline<=$d){ and putting $countTimeline into the for-loop above.