I try run the function exec() to execut another script php. It's work on Windows, but on Linux Server dosen't.
Windows
$str = exec("start /B php test_file.php",$output);
Linux
$str = exec("php test_file.php > /dev/null &",$output);
test_file.php
echo "Test work";
Both scripts are on same folder, when a run on Windows i get a array with the string "Test work", but when i run Linux comand on Linux Server dosen't
EDIT
I try change the comand, as @Robert sugest:
$str = exec("php test_file.php",$output);
echo $str;
var_dump($output);
But that returned this:
array(1147) { [0]=> string(24) "X-Powered-By: PHP/7.0.16" ...
Make sure you use the correct path to both your php binary and the file you want to execute.
Example:
exec('/path/to/php -f /path/to/file.php', $output);
Additionally, if you want to pass parameters to it, you can add them after the php file and read them from the $argv array. php manual $argv
In your case you can do:
exec('/path/to/php -f /path/to/file.php param1 param2 param3', $output);
In the php file you are executing, you can do a
vardump($argv);
Which in my example contains 4 items, $argv[0] is the name of the file you are executing, $argv[1] has the value of param1, etc.