查找包含给定单词并在数组中返回的行

Lets say I have following lines:

How, are you!
Are you there?
Yes, you over there.

I have to display those lines which contains word "there", In my case it should return following array of strings:

["Are you there?", "Yes, you over there."]

What I did is :

$arr = array();
        while (!feof($file)) {
            $line = fgets($file);
            if (strpos($line, $keyword) !== false) {
                $arr[]=$line;
            }
        }
        print_r($arr);
        return;

How can I get the result in ["Are you there?", "Yes, you over there."] format.

Here's a quick way:

$result = preg_grep("/$keyword/", file("/path/to/file.txt"));

• file() creates an array of each line
• grep over the array for the keyword

If you want that literal string, then that is JSON:

$string = json_encode($result);

Regex?

 preg_match_all("/.* there .*|there .*|.* there.*/", $input_str, $output_array);

You can replace the "there" with a variable.

http://www.phpliveregex.com/p/fLn