I want to distribute some personnel in a week every day there are 3 times 7h-15h 15-23h 23h-7h .
The problem that I don't want a person to show more than one time in a day. I want to distribute personnel list to the day of week I try this:
<?php
$input = array("Name1","Name2", "Name3","Name4");
$rand_keys = array_rand($input, 3);
?>
<table border=1>
<tr>
<th> Samedi </th> <th> Dimanche </th> <th> Lundi </th> <th> Mardi </th> <th> Merecredi </th> <th> Jeudi </th> <th> Vendredi </th>
</tr>
<tr>
<?php
$j=1;
for($i=0;$i<7;$i++){
echo "<td>";
for($k=0;$k<3;$k++){
echo $input[$rand_keys[0]] ."7H-15H
" ;
echo $input[$rand_keys[1]] ."15H-23H
" ;
echo $input[$rand_keys[2]] ."23H-7H
" ;
}
echo "</td>";
}
?>
You don't need the second loop for ($k = 0; $k < 3; $k++), because you're already showing each shift with the 3 echo statements.
for($i=0;$i<7;$i++){
echo "<td>
";
echo $input[$rand_keys[0]] ." 7H-15H
" ;
echo $input[$rand_keys[1]] ." 15H-23H
" ;
echo $input[$rand_keys[2]] ." 23H-7H
" ;
echo "</td>
";
}
You're also using the same schedule every day of the week. So one of the people is never being scheduled for the entire week. You probably should shuffle the array each day, not just at the beginning of the script.
for($i=0;$i<7;$i++){
echo "<td>
";
shuffle($input);
echo $input[0] ." 7H-15H
" ;
echo $input[1] ." 15H-23H
" ;
echo $input[2] ." 23H-7H
" ;
echo "</td>
";
}
To keep a person from working two shifts in a row if they're assigned to 23H-7H and then 7H-15H the next day, you can set a variable to that person, and check if the shuffle put them first.
$last_shift = $input[array_rand($input)];
for($i=0;$i<7;$i++){
echo "<td>
";
shuffle($input);
while ($input[0] == $last_shift) {
shuffle($input);
}
echo $input[0] ." 7H-15H
" ;
echo $input[1] ." 15H-23H
" ;
echo $input[2] ." 23H-7H
" ;
$last_shift = $input[2];
echo "</td>
";
}