员工安排时区转换

Hi guys im trying to convert an employee schedule from asia/manila timezone to america/los_angeles but i got error because of the day off schedule when converting it using this code

$datecon = new DateTime($date[$a].' '.$time[$a], new 
DateTimeZone('Asia/Manila'));
$datecon->setTimezone(new DateTimeZone('America/Los_Angeles'));

heres the error

Sunday, 04/07/2019 | DAY OFF Fatal error: Uncaught Exception: DateTime::__construct(): Failed to parse time string (04/07/2019 DAY OFF) at position 11 (D): The timezone could not be found in the database in C:\xampp\htdocs\test\index.php:38 Stack trace: #0 C:\xampp\htdocs\test\index.php(38): DateTime->__construct('04/07/2019 DAY ...', Object(DateTimeZone)) #1 {main} thrown in C:\xampp\htdocs\test\index.php on line 38

<table class="table table-bordered col-lg-6">
<thead class="thead-dark">
<tr>
    <td>Asia/Manila 
    </td>
    <td>America/Los_Angeles
    </td>
</tr>
</thead>
<tbody>
    <?php 
    $date = array('04/07/2019','04/08/2019','04/09/2019','04/10/2019','04/11/2019','04/12/2019','04/13/2019','04/14/2019','04/15/2019','04/16/2019','04/17/2019','04/18/2019','04/19/2019','04/20/2019');
    $time = array('DAY OFF','DAY OFF','12:00 AM','12:00 AM','12:00 AM','12:00 AM','12:00 AM','DAY OFF','11:00 PM','11:00 PM','11:00 PM','1:00 PM','1:00 PM','DAY OFF');
    $day = array('Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday','Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday','Sunday');
    $timezone = 'America/Los_Angeles';
    for($a=0; $a < 14; $a++){
    echo '<tr><td>';
    echo $day[$a].', '.$date[$a].'  | <b>'.$time[$a].'</b>';


    $datecon = new DateTime($date[$a].' '.$time[$a], new 
    DateTimeZone('Asia/Manila'));

    $datecon->setTimezone(new DateTimeZone('America/Los_Angeles'));



    echo '<td>';
    echo $day[$a].', '.$date[$a].'</td>';

    echo '</tr>';

    }
    ?>
</tbody>

Result