从一个不起作用的类中抓取PHP特定的

I am trying to scrape the rating from this particular page

https://www.zomato.com/ncr/between-buns-sda-new-delhi

which is in this code here

<div tabindex="0" aria-label="Rated" data-res-id="18559961" class="rating-for-18559961 rating-div rrw-aggregate level-7">
                                                            4.0<span>/5</span>                                                        </div>

I am trying to use aria-label="rated" to scrape as class has a very long name but its returning empty result

here is my code

<?php

$curl = curl_init('https://www.zomato.com/ncr/between-buns-sda-new-delhi');
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($curl,CURLOPT_USERAGENT,'Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.13) Gecko/20080311 Firefox/2.0.0.13');

$page = curl_exec($curl);

if(!empty($curl)){ //check html return

    $zomato_doc = new DOMDocument;
    libxml_use_internal_errors(true);
    $zomato_doc->loadHTML($page);
    libxml_clear_errors(); //remove errors 

    $zomato_xpath = new DOMXPath($zomato_doc);
    $rate = $zomato_xpath->query('//div[contains(@aria-label,"Rated")]');
        if($rate->length > 0) {
          $node = $rate->item(0);
          echo "{$node->nodeName} - {$node->nodeValue}";
        } 
        else {
          // empty result set
          echo "no result bro";
        }

}
else {
    print "Not found";
}


?>

But everytime I get No result bro as answer, it never parses the information. Please help