将Myscho Echo转换成表格 - 演示文稿和DOM

Two questions in one: First question, mainly about presentation: I'm echo-ing the following code which should create a table. The table should have a single column, but it's being rendered with the elements above the image as a single line. can anyone see why?

<?php   
$sql = "SELECT * FROM catdata WHERE featured='yes' LIMIT 2";
if($result = mysqli_query($link, $sql)){
    if(mysqli_num_rows($result) > 0){
        echo "<table>";
        while($row = mysqli_fetch_array($result)){
            echo "<tr>";
                echo "<td>" . $row['manufacturer'] . "</td>";
            echo "</tr";

            echo "<tr>";
                echo "<td>" . $row['title'] . "</td>";
            echo "</tr";

            echo "<tr>";

                echo "<td><img src=\"6.diesel.png\"></td>";
            echo "</tr>";

            echo "<tr>";    
                echo "<td>" . $row['size'] . "l</td>";
            echo "</tr>";
            echo "<tr>";
                echo "<td>" . $row['mileage'] . "</td>";
            echo "</tr>";
            echo "<tr>";
                echo "<td>" . $row['fitsmodel'] . "</td>";
            echo "</tr>";
            echo "<tr class=\"tablePriceBlock\">";
                echo "<td>£" . $row['pricefitted'] . "</td>";
            echo "</tr>";
            echo "<tr>";
                echo "<td>£" . $row['pricedel'] . "</td>";

            echo "</tr>";
        }
        echo "</table>";
        // Free result set
        mysqli_free_result($result);
    } else {
            echo "No records matching your query were found.";
            }
} else{
            echo "ERROR: Unable to execute $sql. " . mysqli_error($link);
    }
?>

Question 2:

Can I show the second result in a second column, or as a separate table? Also, is it possible to access the $result elements like say, $[manufacturer][1]?

Always look at the emitted source your code generates by either "View Source" or using a tool like curl. You'll find this mistake:

echo "</tr";

You're missing a >.

Many people who write HTML have browser plugins that can link through to an HTML validator to ensure they've got the correct syntax. You may want to find and install one of these.

To generate the second result is a separate table follow the following code.

   echo "<table>";
                            $count = 1;
                           while($row = mysqli_fetch_array($result)){
  if($count == 2){
  echo "<table>";
  echo "<tr>";
  echo "<td>put your code here</td>";
  echo "</tr>"
  echo </table>  

   }else{
                         echo "<tr>";
                         echo "<td>" . $row['manufacturer'] . "</td>";
                            echo "</tr";

                            echo "<tr>";
                                echo "<td>" . $row['title'] . "</td>";
                            echo "</tr";

                            echo "<tr>";

                                echo "<td><img src=\"6.diesel.png\"></td>";
                            echo "</tr>";

                            echo "<tr>";    
                                echo "<td>" . $row['size'] . "l</td>";
                            echo "</tr>";
                            echo "<tr>";
                                echo "<td>" . $row['mileage'] . "</td>";
                            echo "</tr>";
                            echo "<tr>";
                                echo "<td>" . $row['fitsmodel'] . "</td>";
                            echo "</tr>";
                            echo "<tr class=\"tablePriceBlock\">";
                                echo "<td>£" . $row['pricefitted'] . "</td>";
                            echo "</tr>";
                            echo "<tr>";
                                echo "<td>£" . $row['pricedel'] . "</td>";

                            echo "</tr>";
 }
$count ++;
                        }
                        echo "</table>";

As you are limiting your query to only two record so this method is not bad for that and hope this will help.