如何从PHP中的Combobox中获取所选项目的值来自数据库

how do I extract values ​​from the table and selected in the combobox, so that the results are not as below

<?php 
    $id = @$_GET['id'];
    $query  = "SELECT id_rm, tb_rekammedis.id_pasien, nama_pasien, keluhan, tb_rekammedis.id_dokter, nama_dokter, diagnosa, tb_rekammedis.id_poli, nama_poli, tgl_periksa
    FROM tb_rekammedis 
    INNER JOIN tb_pasien USING(id_pasien)
    INNER JOIN tb_dokter USING(id_dokter)
    INNER JOIN tb_poliklinik USING(id_poli) WHERE id_rm='$id'";
    $sql_pasien = mysqli_query($con, $query) or die(mysqli_error($con));
    $data = mysqli_fetch_array($sql_pasien);
    ?>
    <label for="pasien">Nama Pasien</label>
    <select name="pasien" id="pasien" class="form-control" required>
        <option value="<?=$data['id_pasien']?>" selected="selected"><?=$data['nama_pasien']?></option>
        <option value="">- Pilih Pasien -</option>
        <?php 
        $sql_pasien = mysqli_query($con, "SELECT * FROM tb_pasien") or die(mysqli_error($con));
        while($data_pasien = mysqli_fetch_array($sql_pasien)) {
        echo '<option value="'.$data_pasien['id_pasien'].'">'.$data_pasien['nama_pasien'].'</option>';
        }
?>
    </select>

how do I extract values ​​from the table and selected in the combobox