我无法从相同类型内容的php字段值生成drupal 7上的正确视图

I am a student who has been working with drupal 7 for a website and I can not make the following work. (I will try to explain it as clearly as possible).

I have a type of content for example (My selection). This type of content contains different fields. One of them is for example "Agents" (people). Within My selection I have this field added as a type of field "Selection list" and through php, I get a list of the names with the agents in the content type Agents.

This works correctly, and at the time of creating the content my selection I can choose 1 or several Agents.

The problem I have when generating a view to show the agents that I have selected. Imagine that I have created a My selection "Selection 1" and I have chosen two agents. I can not associate the view so that when I create it, I get the photo and the name of those two agents for that "Mi seleccion". In other views that do not depend on taking the contents of the content itself, I have no problems and I associate them well with the node, but here something is failing me. I dont know to associate the node in that Mi seleccion, with it field Agent with the fields on my type of content Agents

I'm going to put a screenshot of the view.

MY problem is that I do not know how to relate the values of my Field Agents in MY selection, that is, its node, so that it only shows me those chosen for that my selection. I get him to show me ALL the agents or none.

Please, I am desperate, if someone can give me 10 minutes of their time and give me a solution, I will thank them forever.

Thank you! Sergio