PHP：省略[]（）{}中包含的字符串部分

Is it possible to make a rule that can simultaneously remove any parts of the string enclosed with [] () and {} in one go, only leaving any part of it?

For example, if I have a string like this:

// Input
$string = 'my(apple)[banana][carrot(orange)]food[supply]';

// Output
$string = 'myfood';

I know how to select parts of a string that is enclosed with brackets, but in this case I want to select any parts that isn't enclosed instead.

Here's my current regex where I'm stuck, which I can select the enclosed characters:

\[.*?\]|\(.*?\)|\{.*?\}

This is work around to achieve this,

$string = 'my(apple)[banana][carrot(orange)]food[supply]{test}';
echo preg_replace('/{(.*?)}|\[.*?\]|\([^)]+\)/","",$string);

Here is working demo.

I found out the answer:

  $var = 'my(apple)[banana][carrot(orange)]food[supply]';

  echo preg_replace('/\[.*?\]|\(.*?\)|\{.*?\}/', '', $var);