正在执行PHP更新查询,但不更新凭据

I have a form tag on my site that leads to the PHP page with email and/or/without description. Based on that the code generates a query, the query needs to update these credidentials. That part of the code works and has been tested. The problem is that the database is not updating the e-mail credidential, but if i put it to update the description it does so. The code has 3 checks, if the user puts only his email, if he puts only his description or puts both. Based on that the code works like this :

<?php
session_start();
include_once 'connection.php';
$id = $_SESSION['user_id'];
if(isset($_POST['emailChange']) || isset($_POST['descChange'])){
       $desc = $_POST['descChange'];
       $email = $_POST['emailChange'];
       if(empty($email)){
           $query = "UPDATE users SET description = :descr WHERE user_id= :id ;";
           $stmt = $conn->prepare($query);
           $stmt->bindParam(":descr", $desc);
       } else if(empty($desc)){
           $query = "UPDATE users SET user_email= :email WHERE user_id= :id ;";
           $stmt = $conn->prepare($query);
           $stmt->bindParam(":email", $email);
       } else{
           $query = "UPDATE users SET description = :descr AND user_email = :email WHERE user_id= :id;";
           $stmt = $conn->prepare($query);
           $stmt->bindParam(":email", $email);
           $stmt->bindParam(":descr", $desc);
       }
       if(!filter_var($email, FILTER_VALIDATE_EMAIL)){
           header("Location: ../profile.php?error=invalidEmail");
           exit();
       }
           $stmt->bindParam(":id", $id);
           $stmt->execute();
   }

The form itself looks like this :

 <form action="assets/upload.php" method="POST">
     <input type="text" name="emailChange" class="inputs" id="changeEmail" placeholder = "Enter your new E-mail">
     <input type="text" name="descChange" class="inputs" id="changeDesc" placeholder="Enter your description">
     <button type="submit" id="btnconfirmCreds" name="changeCreds">Confirm Changes</button>
 </form>

The names in the database looks like this :

[user_id][user_username][user_email][user_password][role_id][user_image][description][num_of_posts]

You should set up PDO error logging.


From Comments; paraphrased for clarity:

My user_id column is int(11) auto_increment

Your problem is you are trying to insert a string value into a numerical column in MySQL.

user_id / id in database parlance is usually a numerical value, but you have not set the value type in your SQL, so it defaults to string.

Because your :id value is a numeric value in PHP you need to do this:

$stmt->bindParam(":id", $id, 'i');  // i = integer type. 

It is highly recommended to explicitly set the value of the data type supplied each and every time .

If the data given to the PDO does not match the value-type given, then the PDO transaction will void and will not complete. This is a security measure.

For example:

$id = 3;
$stmt->bindParam(":id", $id); 

This is the same as saying:

$stmt->bindParam(":id", 3, 's'); // default type value is 's' for string. 

Obviously the value 3 is not a string so this transacion ($stmt) is never performed.


i assume it's because it views the description as a special word, if that is true then i should change the name in my database. Thoughts?

"description" is neither a Keyword or a reserved word in MySQL 5.5-->5.7
(in MySQL 8.0.4 DESCRIPTION is a keyword but is not a reserved word)
You can view a list of MySQL Keywords and Reserved words .

Some notes about the logic:

if(isset($_POST['emailChange']) || isset($_POST['descChange']))
{
    $desc = $_POST['descChange'];
    $email = $_POST['emailChange'];
    ...

First you check, if at lease one parameter exists, but then you access both. You can argue, that the form send always both, but never believe user input: Manipulating data is so easy!

Either change your if(...) to:

if( isset($_POST['emailChange']) && isset($_POST['descChange']) )

The following line is a shorter form with identical semantics:

if( isset( $_POST['emailChange'], $_POST['descChange'] ) )

The other ways is to change the 2 other lines, for example by:

    $desc  = isset($_POST['descChange'])  ? $_POST['descChange']  : '';
    $email = isset($_POST['emailChange']) ? $_POST['emailChange'] : '';