Yii第二个查询参数

I have query to my database using Yii

$query = Task::find()
        ->where([Task::tableName().'.parent_id' => 0]);
$query->leftJoin(TaskModel::tableName(), [TaskModel::tableName().'.task_id' => Task::tableName().'.id']);
$query->andWhere([TaskModel::tableName().'.format' => null]);
$rows = $query
        ->offset($pages->offset)
        ->limit($pages->limit)
        ->orderBy([
            Task::tableName().'.status' => SORT_DESC,
            Task::tableName().'.`estimated_date`=0' => SORT_ASC,
            Task::tableName().'.estimated_date' => SORT_ASC
        ])
        ->all();

But that doesn't work, because at leftJoin, when I set relations between tables, second parameter sets string.

rawSql of my query:

SELECT `task`.* 
FROM `task` LEFT JOIN `task_model`
ON `task_model`.`task_id`='{{%task}}.id'
WHERE (`task`.`parent_id`=0) AND (`task_model`.`task_id` IS NULL)

You should use string in this case:

$query->leftJoin(TaskModel::tableName(), TaskModel::tableName() . '.task_id = ' . Task::tableName() . '.id');

This case is explicitly mentioned in documentation:

Note that the array format of where() is designed to match columns to values instead of columns to columns, so the following would not work as expected: ['post.author_id' => 'user.id'], it would match the post.author_id column value against the string 'user.id'. It is recommended to use the string syntax here which is more suited for a join:

'post.author_id = user.id'