比较数组键并在php中获取值

I have array which show result like this :

Array ( [standards_id] => 1 
    [value] => sory 
    [order] => 10
) 
Array ( [standards_id] => 1 
    [value] => javid 
    [order] => 3
) 
Array ( [standards_id] => 1 
    [value] => saleem 
    [order] => 4
).

I want to check the array key ,if it is "value" then i want to concatenate its value.I try code like this but not successeded.

$row = array(.....);
 $vali = '';
foreach ($row as $key => $value) {

        if( $value[$key] == 'value'){

                echo  $vali .= $value['value'].",";
        }
    }  

I want to do it in one loop.$row contains multiple arrays like above 3.$row contains all the records that are fetched from data base.hope you understand what $row is.

Use isset() to find out whether the key 'value' is present in each element of $row; you don't need a loop for that at all:

foreach ($row as $data) {
    if (isset($data['value'])) {
       $vali .= $data['value'] . ',';
    }
}

Alternatively, you can build an array with the values:

$values = array();
foreach ($row as $data) {
    if (isset($data['value'])) {
        $values[] = $data['value'];
    }
}
echo join(',', $values);

You need this:

    foreach ($row as $key => $value) {

            if( $key == 'value'){

                     $vali .= $value.",";
            }
        }

echo $vali;

$row = array('standards_id' => 1, 'value' => 'saleem', 'order' => 4);
$vali = '';
foreach ($row as $key => $value) {
    if( $key == 'value'){
        $vali .= $value . ",";
    }
}
echo $vali;

Your naming suggests that $row contains just:

Array ( [standards_id] => 1 
    [value] => sory 
    [order] => 10
) 

There is no reason to loop over such a structure. You can test if this 'row' contains a value with

if( isset( $row['value'] ) ) { 
  $vali .= $row['value'] . ', ';
}

If you have a variable $myRows containing these arrays, you can loop over them using

foreach( $myRows as $k => $row ) { ... }

In this case $row contains the array and you can use the first code to append the value to $vali.