For example i have an array like this $array = ('a' => 2, 'b' => 1, 'c' => 4);
and i need to swap a
with c
to get this $array = ('c' => 4, 'b' => 1, 'a' => 2);
. Wht is the best way for doing this without creating new array? I know that it is possible with XOR, but i also need to save indexes.
If you want to purely swap the first and the last positions, here's one way to do it:
$first = array(key($array) => current($array)); // Get the first key/value pair
array_shift($array); // Remove it from your array
end($array);
$last = array(key($array) => current($array)); // Get the last key/value pair
array_pop($array); // Remove it from the array
$array = array_merge($last, $array, $first); // Put it back together
Gives you:
Array
(
[c] => 4
[b] => 1
[a] => 2
)
Working example: http://3v4l.org/r87qD
Update: And just for fun, you can squeeze that down quite a bit:
$first = array(key($array) => current($array));
$last = array_flip(array(end($array) => key($array)));
$array = array_merge($last, array_slice($array,1,count($array) - 2), $first);
Working example: http://3v4l.org/v6R7T
Update 2:
Oh heck yeah, we can totally do this in one line of code now:
$array = array_merge(array_flip(array(end($array) => key($array))), array_slice($array,1,count($array) - 2), array_flip(array(reset($array) => key($array))));
Working example: http://3v4l.org/QJB5T
That was fun, thanks for the challenge. =)
array_splice
would be perfect, but unfortunately it doesn't preserve the keys in the inserted arrays. So you'll have to resort to a little more manual slicing and dicing:
function swapOffsets(array $array, $offset1, $offset2) {
list($offset1, $offset2) = array(min($offset1, $offset2), max($offset1, $offset2));
return array_merge(
array_slice($array, 0, $offset1, true),
array_slice($array, $offset2, 1, true),
array_slice($array, $offset1 + 1, $offset2 - $offset1 - 1, true),
array_slice($array, $offset1, 1, true),
array_slice($array, $offset2 + 1, null, true)
);
}