php（array） - > mysql（带有外键的多行）更新表中id和行号变化的特定行

$schoolinfo = mysqli_prepare($con, "UPDATE table SET firstname=?, lastname=? from school where   foreignkey='$id'");

mysqli_stmt_bind_param($schoolinfo,'ss', $firstname, $lastname)


for ($i=0;$i<count($_POST['row']);$i++){     
$firstname = mysqli_real_escape_string($con, $_POST['firstname'][$i]);
$lastname = mysqli_real_escape_string($con, $_POST['lastname'][$i]);
mysqli_stmt_execute($schoolinfo);
}

This updates all rows with the same firstname and lastname.

I want to update rows from selection where foreignkey = '$id' and rownumber ='i'

Any queries or subqueries out there?

just remove this from school from your update query and give a name to your table .

like that

 $schoolinfo = mysqli_prepare($con, "UPDATE school SET firstname=?, lastname=? where   foreignkey='$id'");

you mixed between SELECT and UPDATE.

i dont know if im wrong or , you have binded firstname and lastname before the loop .

try this

$schoolinfo = mysqli_prepare($con, "UPDATE school SET firstname=?, lastname=? WHERE foreignkey='$id'");

for ($i=0;$i<count($_POST['row']);$i++){     
$firstname = $_POST['firstname'][$i];
$lastname = $_POST['lastname'][$i];
mysqli_stmt_bind_param($schoolinfo,'ss', $firstname, $lastname)
mysqli_stmt_execute($schoolinfo);
}

Try this:

$schoolinfo = mysqli_prepare($con, "UPDATE school SET firstname=?, lastname=?
                                    WHERE foreignkey=? and rownumber = ?");

mysqli_stmt_bind_param($schoolinfo,'sssi', $firstname, $lastname, $id, $i);

for ($i=0;$i<count($_POST['row']);$i++){     
    $firstname = $_POST['firstname'][$i];
    $lastname = $_POST['lastname'][$i];
    mysqli_stmt_execute($schoolinfo);
}

You didn't have rownumber in the query. And it's best to use bind_param for all variables that you're substituting.