i am trying to extract the word in between the last / and the second last / - i.e. food in the following PHP example.
$string = https://ss1.xxx/img/categories_v2/FOOD/fastfood (would like to replace $string to food)$string = https://ss1.xxx/img/categories_v2/SHOPS/barbershop (would like to replace $string to shops)I am new to regex and tried /[^/]*$ - however that is returning everying after the last /.. any help would be appreciated.. thanks!
I am using PHP.
You can use this:
$result = preg_replace_callback('~(?<=/)[^/]+(?=/[^/]*$)~', function ($m) {
return strtolower($m[0]); }, $string);
Pattern details:
~ # pattern delimiter
(?<=/) # zero width assertion (lookbehind): preceded by /
[^/]+ # all characters except / one or more times
(?=/[^/]*$) # zero width assertion (lookahead): followed by /,
# all that is not a / zero or more times, and the end of the string
~ # pattern delimiter
Use:
preg_match('#/([^/]*)/[^/]*$#', $string, $match);
echo $match[1];
You could also use:
$words = explode('/', $string);
echo $words[count($words)-2];
Regex:
(\w+)(/[^/]+)$
PHP code:
<?php
$string = "https://ss1.xxx/img/categories_v2/FOOD/fastfood";
echo preg_replace("@(\w+)(/[^/]+)$@", "food$2", $string);
$string = "https://ss1.xxx/img/categories_v2/SHOPS/barbershop";
echo preg_replace("@(\w+)(/[^/]+)$@", "shops$2", $string);
?>