I'm trying to make an android app using fuzzy (have yet to make the whole fuzzy calculation) so the calculations will be done in php. For starter I was just making a simple calculation in php first and trying to send to the android. but it doesn't show anything..there no error either.
Here's the simple example of my php code calc.php
<?php
$calcresult = 56 * 100 * 2051 / 49;
echo json_encode($calcresult);
?>
and this is my java code JSONActivity.class
package com.example.ta2;
import java.io.BufferedReader;
import java.io.InputStream;import java.io.InputStreamReader;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONObject;
import android.app.Activity;
import android.os.Bundle;
import android.widget.TextView;
import android.widget.Toast;
public class AturanKonsumsi extends Activity {
private JSONObject jObject;
private String xResult ="";
private String url = "http://10.0.2.2/calc.php";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.daftarmakanan);
TextView txtResult = (TextView)findViewById(R.id.TextViewResult);
xResult = getRequest(url);
try {
parse(txtResult);
} catch (Exception e) {
e.printStackTrace();
}
}
private void parse(TextView txtResult) throws Exception {
jObject = new JSONObject(xResult);
JSONArray menuitemArray = jObject.getJSONArray("calcresult");
String sret="";
for (int i = 0; i < menuitemArray.length(); i++) {
System.out.println(menuitemArray.getJSONObject(i)
.getString("calcresult").toString());
sret +=menuitemArray.getJSONObject(i).getString(
"calcresult").toString()+"
";
}
txtResult.setText(sret);
}
public String getRequest(String Url){
String sret="";
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet(Url);
try{
HttpResponse response = client.execute(request);
sret =request(response);
}catch(Exception ex){
Toast.makeText(this,"Gagal "+sret, Toast.LENGTH_SHORT).show();
}
return sret;
}
public static String request(HttpResponse response){
String result = "";
try{
InputStream in = response.getEntity().getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder str = new StringBuilder();
String line = null;
while((line = reader.readLine()) != null){
str.append(line + "
");
}
in.close();
result = str.toString();
}catch(Exception ex){
result = "Error";
}
return result;
}
}
when I run the android app it doesn't show the value in $calcresult and there's no error either. thanks for your help
calcresult is not referenced by the json your php script is producing. Check the output. To make your java code work, you'll need to create the json like so:
<?php
$calcresult = 56 * 100 * 2051 / 49;
$json = array( 'calcresult' => array( $calcresult ) );
echo json_encode($json);
?>
Alternately, you can simplify your java.