PHP sql变量引用两个函数[关闭]

If I want use the variable $post->user_id in two functions like this it doesn't work. Why?

foreach ($usermeta as $post) {
    echo $post->user_id;
    echo $post->name;
    echo $post->team; 
}

function nicoupdate($post->user_id) {
    update_usermeta( $post->user_id , 'ptotali', $_POST['ptolti'] );
}

I don't understand.

Still doesn't work:

$sql="SELECT `user_id`,
 max(case when  `meta_key` = 'name' then `meta_value` end)  as name ,
 max(case when  `meta_key` = 'team' then `meta_value` end) as team ,
 max(case when  `meta_key` = 'ptotali' then `meta_value` end) as points ,
 FROM wp_usermeta


 GROUP BY `user_id`   

 ORDER BY points DESC";

global $wpdb;
$usermeta = $wpdb->get_results($sql) or die(mysql_error());

foreach ($usermeta as $post) {
    echo $post->user_id;
    echo $post->name;
    echo $post->team; 
}

function nicoupdate($user_id) {
    update_usermeta( $user_id , 'ptotali', $_POST['ptolti'] );
}

What's wrong? If I put manually the user_id for example 3 it works.

Well - I've never seen that notation before. $usermeta as $post is usually only used in a foreach statement. So first you need to drop the $usermeta as part of the function definition.

function nico($post)
   ....

Secondly, you are declaring another function with a variable, not with a name. Try this

function nicoupdate($user_id)
   ....

Then call it with:

noicoupdate($post->user_id);