在搜索脚本中获取错误[php，mysqli]

I am trying to create a very simple and basic search script.

Here is what I have done so far:

include('config.php');

$search_token =$_POST['search_token'];

$search_query = mysqli_query($conn, "SELECT Forname FROM idea WHERE post_des LIKE '%$search_token%'");

while($row = mysqli_fetch_array($search_query))
  {

  $idea_body = $row['post_des'];

  echo $idea_body;
}

But when I execute this, I am having the following Warning:

Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in F:\Server\xampp\htdocs\p\c3\search.php on line 34

Any help for this situation?

You probably have a problem in your query, try:

$search_query = mysqli_query($conn, "SELECT Forname FROM idea WHERE post_des LIKE '%$search_token%'") or die(mysqli_error($conn));

To debug your query.

Your query is failing and returning a false value.

put this after your mysqli_query() to see whats going on.

if (!$search_query) {
    printf("Error: %s
", mysqli_error($con));
    exit();
}

for more information.

http://www.php.net/manual/en/mysqli.error.php