这是一道本科的编程问题，因为我刚学一年还不大清楚，请问有人愿意解答吗？谢谢

题目要求都在图片里，要求用C++。谢谢

#include <stdlib.h>
#include <string.h>
#include <iostream>
using namespace std;

int* initdkntor(int n, int * brokens, int m)
{
    int * p = (int *)malloc(sizeof(int) * n);
    memset(p, 0, sizeof(int) * n);
    for (int i = 0; i < m; i++)
    {
        for (int j = brokens[i * 2] - 1; j < brokens[i * 2 + 1]; j++)
            p[j] = 1;
    }
    return p;
}

int* tryit(int *seed, int n, int a, int b)
{
    int * p = (int *)malloc(sizeof(int) * n);
    memcpy(p, seed, sizeof(int) * n);
    for (int i = a - 1; i < b; i++) p[i] = 0;
    return p;
}

int check(int *p, int n)
{
    for (int i = 0; i < n; i++) if (p[i]) return 1;
    return 0;
}

int solve(int *seed, int seedcost, int n, int *sp, int spn)
{
    if (!check(seed, n)) return seedcost;
    if (!spn) return -1;
    int min = -1;
    for (int i = 0; i < spn; i++)
    {
        int * seed1 = tryit(seed, n, sp[i*3], sp[i*3+1]);
        int cost = solve(seed1, seedcost + sp[i*3+2], n, sp + 3 * (i+1), spn - i-1);
        if (cost != -1)
            if (cost < min || min == -1) min = cost;
    }
    return min;
}

int main()
{
    int s;
    int n;
    int m;
    cin >> n >> m >> s;
    int * bk = new int[n * 2];
    for (int i = 0; i < n; i++)
        cin >> bk[i*2] >> bk[i*2+1];
    int * sp = new int[m * 3];
    for (int i = 0; i < m; i++)
        cin >> sp[i*3] >> sp[i*3+1] >> sp[i*3+2];
    int * dkntor = initdkntor(s, bk, n);
    int result = solve(dkntor, 0, s, sp, m);
    cout << result << endl;
    return 0;
}

在线编译通过
https://ideone.com/195uxV

建议你贴文本，而不是图片，英文看不懂

不知道你这个问题是否已经解决, 如果还没有解决的话:

• 这有个类似的问题, 你可以参考下: https://ask.csdn.net/questions/879028

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