Let's say I have two websites. A Java web app running at www.server100.com, and a PHP web app running at www.server200.com.
Let's say I have a servlet http://www.server100.com/webapp1/getImageServlet that returns the following HTML content, where the filename in the html (ABC123.jpg) is a different filename for every hour of the day:
<div id="dynamicImage">
<img src="http://www.server100.com/ABC123.jpg">
</div>
Now, let's say I have a PHP file here: http://www.server200.com/test1.php. How do I include the HTML that results from the servlet in my PHP file?
I'm thinking I want to do something like ...
<?php
Print "<html><body>";
Print "Hi! Let's see this hour's image!";
include "http://www.server100.com/webapp1/getImageServlet";
Print "</body></html>";
?>
Any ideas are greatly appreciated! And would it simplify things if the Java app and the PHP app were running on the same server? Thanks!
I think I have figured it out ...
Print file_get_contents("http://www.server100.com/webapp1/getImageServlet");
... seems to do what I need.
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<meta name="description" content="">
<meta name="viewport" content="width=device-width, initial-scale=1">
<title>Title</title>
</head>
<body>
<?php
//your PHP goes here
file_get_contents("http://www.server100.com/webapp1/getImageServlet");
?>
</body>
</html>
save this as whatever.php
if your servlet outputs HTML just do this
<?php
$handle = fopen("http://www.server100.com/webapp1/getImageServlet", "r");
$contents = '';
while (!feof($handle)) {
$contents .= fread($handle, 8192);
}
fclose($handle);
echo $contents; //printing it all out
?>
also echoing file_get_contents() should work just fine