I recently received -3 ratings for my recent question though the solution wasn't provided. My apologies if I posted something which I shouldn't have.
Alright so it is related to that ques only I have this code:
$data = mysql_connect("localhost", "user", "pass");
mysql_select_db("dbname");
$data = mysql_query("SELECT `location` FROM `upload` WHERE `name` = '".$result['name']."'")
or die(mysql_error());
$info = mysql_fetch_array( $data );
$display_url = $info['createlink'];
So when I echo $display_url it returns nil value and in db I checked the createlink field and the value stored there is a link. And when I use
$display_url = $info['location'];
It returns perfect value.
~~The field at createlink contains 'http://www.exdomain.com/create/create.php?t=BATMAN_SLAPPING_ROBBIN.jpg'
~~The field at location contains 'http://www.exdomain.com/create/img/BATMAN_SLAPPING_ROBBIN.jpg'
You're not requesting the createlink
field from the table, only location
. Change your query to this:
$data = mysql_query("SELECT `location`,`createlink` FROM `upload` WHERE `name` = '".$result['name']."'")
You should also move away from the deprecated mysql_* functions and switch to PDO/mysqli so that your code will work in future versions of php. This will also allow you to parametrize your queries to prevent SQL injection.