PHP包含在DIV样式背景中

I've got a rotating image that changes daily and I'm trying to make this the background image of a DIV so I can have a menu over it. For some reason it just displays all the information inside the includes file instead of showing the daily image?

<div styles="background-image: url(<?php include('includes/promotions.php'); ?>)">MENU</div>

Inside the includes file:

<SCRIPT LANGUAGE="JavaScript">
today = new Date();
day = today.getDay();
arday = new Array("images/daily-offers/sunday.png", "images/daily-offers/monday.png", "images/daily-offers/tuesday.png", "images/daily-offers/wednesday.png", "images/daily-offers/thursday.png", "images/daily-offers/friday.png", "images/daily-offers/saturday.png");
document.write("<img src='"+arday[day]+"'>");
</script>`

I'm kind of new to this but I appreciate the help!

You are trying to put javascript into the style attribute of a div, this isn't possible. Either you need to have php code come up with the filename instead of using an include, or you need to create the div give it an id the use javascript (outside the div's style) to change the background-image.

<div id='changeme'>Menu</div>

<SCRIPT LANGUAGE="JavaScript">
    today = new Date();
    day = today.getDay();
    arday = new Array("images/daily-offers/sunday.png", "images/daily-offers/monday.png", "images/daily-offers/tuesday.png", "images/daily-offers/wednesday.png", "images/daily-offers/thursday.png", "images/daily-offers/friday.png", "images/daily-offers/saturday.png");
    //ASSUMING YOU HAVE JQUERY
    $('#changeme').css('background-image',arday[day]);
</SCRIPT>

Or simply use php:

<?php
$arday = array("images/daily-offers/sunday.png", "images/daily-offers/monday.png", "images/daily-offers/tuesday.png", "images/daily-offers/wednesday.png", "images/daily-offers/thursday.png", "images/daily-offers/friday.png", "images/daily-offers/saturday.png");
$day = date('w');
?>
<div styles="background-image: url('<?php echo $arday[$day]; ?>')">MENU</div>

Or if the naming convention of the images is always the same you could simply do:

<div styles="background-image: url('images/daily-offers/<?php echo strtolower(date('l')); ?>.png')">MENU</div>

You can set the backgroundImage like this:

document.getElementById("mymenu").style.backgroundImage="url(...)";

Your code could go like this:

<div id="mymenu">MENU</div>

<SCRIPT LANGUAGE="JavaScript">
today = new Date();
day = today.getDay();
arday = new Array("images/daily-offers/sunday.png", ...);
document.getElementById("mymenu").style.backgroundImage="url('"+arday[day]+"')";
</script>`

You can't execute javascript inside an attribute like that.

You could try this - change the contents of your includes/promotions.php file to the following:

<?php
$day = strtolower(date('l'));
echo '<img src="images/daily-offers/' . $day . '.png">';
?>

Additionally, the attribute on your div should be style, not styles.

I would not use PHP to do that. I would right the following javascript code at the page where you showing right now the div with the background.

<div id="bgdiv">MENU</div>

<SCRIPT LANGUAGE="JavaScript">

    today = new Date();
    day = today.getDay();
    arday = new Array("images/daily-offers/sunday.png", "images/daily-offers/monday.png", "images/daily-offers/tuesday.png", "images/daily-offers/wednesday.png", "images/daily-offers/thursday.png", "images/daily-offers/friday.png", "images/daily-offers/saturday.png");
    document.getElementById('bgdiv').style.backgroundImage = "url(' + arday[day] + ')";

</script>