Sorry I am new to php and am getting very confused on a bit of code I am working on.
So I get that intTotal += $value; would just add the value to the intTotal but how does the $intTotal += '0x0'.$value; works? I am getting all sorts of random differences when I chance the 0x0 to something else as well.
Thanks
$intTotal += '0x0'.$value; converts $value from hexadecimal number in string to format usable by php and then adds it to $intTotal (after typecasting from string to int).
Edited to add clarity.
0x0 is just a regular 0 in hexadecimal representation that gets cast to string '0' when used with the variable syntax
$value is apparently a string representing a number in hexadecimal.
The string concatenation (the . operator) prefixes it with 0x0, the 0x prefix is used to denote a hexadecimal number (the extra zero is superfluous).
So for example if $value = "f", this will produce 0x0f. This will then be converted to the integer 15 by PHP, and added to $intTotal.